Precision error tensors?
In previous posts I talked about precision error matrices as being tensors. Boy, was I wrong! This is another case of my intuition getting way ahead of my math and science. I know just enough math to shot myself in the foot with these speculations. I’ll explain.
Matrices are multi-dimensional arrays of numbers. A two-dimensional matrix needs two indices and to specify a component . A three-dimensional matrix would need three indices and so on. Tensors can be thought of as matrices but the converse is not true. Not all matrices are tensors. That is where I went wrong.
Tensors are multi-dimensional geometrical objects. Yes, they can be represented by matrices but their true hallmark is that they transform correctly under coordinate transformations. The simplest example of the geometrical nature of tensors can be made with a vector. Take a vector drawn on a sheet of paper. No coordinate system has been drawn on the paper. The vector exists independent of any coordinate system. It has a length, for example, and we need no coordinate system to measure it — just a ruler. Two different coordinate systems can be put on the paper that would result in completely different components for the vector. What makes the vector a tensor is that given a coordinate transformation from one system to the next the vector transforms in such a way that both coordinate systems agree on the length of the vector.
This is the geometrical signature of tensors. Different coordinate systems (observers in the parlance of General Relativity) may have different components for the matrices they use to represent a tensor. But they agree on geometrical properties such as the length of a vector or the area of a polygon.
My claim that precision error matrices can be made into tensors may be correct, but I definitely have not proven it until I can show that the tensors I define transform properly under coordinate transformations.